25 lines
294 B
Python
25 lines
294 B
Python
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import re
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text = """
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#BS
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#BC
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RESULT
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LB1 21406.00
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LB2 22073.00
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LB3 15407.00
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LB4 20382.00
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LS1 0.00
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LS2 0.00
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LS3 0.00
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LS4 0.00
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REND
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"""
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pattern = re.compile(r'(LB[1-4])\s+([\d.]+)')
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matches = pattern.findall(text)
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for match in matches:
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label, value = match
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print(f'{label}: {value}')
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